In the given figure, AP = 2 cm, BP = 6 cm and CP = 3 cm Find DP :

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समांतर चतुर्भुज ABCD के विकर्ण BD पर दो बिंदु P और Q इस प्रकार स्थित हैं कि DP = BQ है। दर्शाइए कि Δ APD ≅ Δ CQB AP = CQ Δ

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